<Tri-2025-2263> hint 

Bisector of angle A cut BC and the circumcircle s at A', A" respectively.

Triangles A'AB' and A'AB are congruent, <AB'A'=<ABA'=<B

Since <AA"C=<ABC=<A'B'A.  A" lies on the circumcircle of triangle CB'A', A"=Q

<A'CA"=<A"AB=<A/2. Hence  angle between AA" and tangent line at A" is <A/2=<A"AC=<A'CA"

Hence tangent line  at Q(=A")is parallel to AC