Advanced Geometric Problem & Solution (Twice a week update) Now 4684 problems posted.
<Tri-2025-2261>, hint
Since C'K is diameter <C'A'K=<C'A'D=90 and <DC'A'=A/2+C/2 Hence <A'DC'=C/2
CA'=CB', <A'DC' =C/2, <ACB=C Hence C is the center of circle A'B'D
Thus CD=CB'=CA' is the radius.
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