Advanced Geometric Problem & Solution (Twice a week update) Now 4800 problems posted.
<Tri-2026-2334>, hint
<Tri-2026-2337>, general, others
<Tri-2026-2336>, general , others
<South Africa MO 2019>
<Tri-2026-2335>, hint
since HPDEF are concyclic
EF/sin EHF=EF/sinA=2PH---<1>, BC/sinA=2R---<2>
<1>/<2>=EF/BC= 2PH/2R. Similarly DE/AB=FD/AC=2PH/2R
Two triangles are similar Hence ratio of their areas is (2PH/2R) x (2PH/2R)
<Tri-2026-2335>, general, similar
<South Africa MO 2018>