Advanced Geometric Problem & Solution (Twice a week update) Now 4923 problems posted.
<Tri-2026-2818>, hint
<Tri-2026-2818>,general. bisector
<Taiwan Math TST3 2014>
<Tri-2026-2817>, hint
<Tri-2026-2817>, general. center
<Taiwan MO 2002>
<Tri-2026-2816 >, hint
Since M is the center of circle ABPQ ,by Brocard theorem M is the orthocenter 0f triangle CHT and CMㅗTH.