<Cir-2026-800>, hint

Since CPQ is isosceles PQ ㅗCO (O;enter of circle ABC) Triangles CLA and CNA are congruent (KAxKC=KPxKQ=KLxKN, A,N,C,L are concyclic <CLA=<CNA=90,CL=CN, AC common)

<COB=2<CAB=<LAB hence AL//CO and COㅗPQㅗAL

<Cir-2026-800>, angle

<Singapore MO 2010>

 

<Cir-2026-799 >, hint

 <Cir-2026-799>, tangent

<Singapore MO 2009>

<Tri-2026-2307>, hint