Advanced Geometric Problem & Solution (Twice a week update) Now 4818 problems posted.
<Cir-2023-751>, hint
CE=2R sin<BDC cos<BCD, ED=2Rsin<BCD cos<BDC . Let <BDC=a, <BCD=x
CE ED=R R sin2x sin2a. Hence 2x=90=<BOD. and <BED=90
Hence B,E,O,D is concyclic.
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