Advanced Geometric Problem & Solution (Twice a week update) Now 4632 problems posted.
<Tri-2023-2071>, hint
AF=FP, <BFD=<A, so <BAD=<A/2. similarly <FAQ=<A/2
AR is the bisector of <A <XAR=<A/2-(90-B)=(B-C)/2,
<XRA=<B+<A/2-90=(B-C)/2. Hence XA=XR
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