Advanced Geometric Problem & Solution (Twice a week update) Now 4841 problems posted.
<Tri-2024-2089>, hint
Inradius r of triangle ABC: a+c-b=2r r=(bsinC+bcosC-b)/2=b/2(sinC+cosC-1)
Since triangles ABC , BHC, AHB are similar
r'=b sinC/2 (sinC+cosC-1), r"= bcosC/2 (sinC+cosC-1))
rxr=r'x r'+r"x r"
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