Advanced Geometric Problem & Solution (Twice a week update) Now 4632 problems posted.
<Tri-2024-2084>, hint
Let circumcircle of APC meets BC in N. N on AD.Then <PAN=<PCN=@
<PAB=<PKB=A/2-@ Hence <KBC=180-A/2.
Since <CBD=A/2. K,B,D are collinear
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