Advanced Geometric Problem & Solution (Twice a week update) Now 4727 problems posted.
<Tri-2024-2098>, hint
Since ABM is equilateral, <CAM=30, <AMC=120 . ,CAM=30
Since ME is parallel to AC <EMB=30 and <DBC=30 and <MBE=90+30=120.
Since ME is perpendicular bisector of AB, triangles AEM and BEM are congruent
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