Advanced Geometric Problem & Solution (Twice a week update) Now 4563 problems posted.
<Tri-2024-2115>, hint
Let AP/BP=t/1-t
AS=t cosA, BT=(1-t) cosB . Since ST// AB AS/BT=AC/BC
t cosA/(1-t) cosB= 2R sinB/2R sin A.
Hence AP/BP=sinB cosB/ sinA cosA] sin2B/sin2A
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