Advanced Geometric Problem & Solution (Twice a week update) Now 4567 problems posted.
<Tri-2024-2118> hint
By Ceva's theprem; let <PCA=x
(sinPCB/sin<PCA ) x(sinPAC/sinPAB) x(sinPBA/sinPBC) =(sin(50+x)/sin(50-x) (sin 10/sin30)
sin(50-x)=2 sin10 sin (50+x) x=30
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