<Tri-2024-2118> hint

By Ceva's theprem; let <PCA=x

(sinPCB/sin<PCA ) x(sinPAC/sinPAB) x(sinPBA/sinPBC) =(sin(50+x)/sin(50-x) (sin 10/sin30)

sin(50-x)=2 sin10 sin (50+x)  x=30

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