Advanced Geometric Problem & Solution (Twice a week update) Now 4563 problems posted.
<Cir-2024-769>, hint
<PQA=x, <ACP=y, then <PO'Q=2x=<PO"C( Triangles O'PQ and O"PC are similar)
Hence CBA=1/2 <CO"P(2x)+1/2<AO"P(2y)=x+y
<CAB=<APC+<CQA=y+x. Hence <CBA=<CAB
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