<Cir-2024-769>, hint


<PQA=x, <ACP=y, then <PO'Q=2x=<PO"C( Triangles O'PQ  and O"PC are similar)

Hence  CBA=1/2 <CO"P(2x)+1/2<AO"P(2y)=x+y

<CAB=<APC+<CQA=y+x. Hence <CBA=<CAB

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