<Tri-2024-2138>, hint

Let<ABF=y, <CAB=x  EG//CD   EG meets AB  at  H.

<BEG=y---> <AHE=<BEG+<ABF=y+y=2y

Triangles CBA and  AHE are similar ---> <AEH=<CAB=x

Triangle AEF is isosceles  (<AEF=<AFE=x+y)

Triangles EAG  and AFB are congruent (AE=AF  <AEG=<FAB=x <AGE=<FBA=y)