<Cir-2024-775>, hint

Let <DEB=x, then <O'AD=>O'DA=x=<O"AC=<O"CA

Hence <DO'C=<CO"D=180-2x   ---> CDO"O" are concyclic

 Since ABㅗO'O" DO'//AB,(<O"AB=<O"DO'=x) <DO'O"=90

Since CDO'O" are cyclic <DCO"=90


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