Advanced Geometric Problem & Solution (Twice a week update) Now 4502 problems posted.
<Tri-2024-2148>, hint
HADB is a parallelogram <ADB=<AHB= 180-<C . So
D lies on the circumference of triangle ABC <DAE=90-A +90 -B=C
Similarly <DEF=<DBF=<DAE=<C
Hence AB=DE=DF
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