Advanced Geometric Problem & Solution (Twice a week update) Now 4502 problems posted.
<Cir-2024- 777>, hint
Let line KM cut circle w at L' and <AKM=x, <MAK=y O is the center of circle w
Since <LQO=<QLO=x+y, <LOQ=180-2(x+y), <QOB=2y. Hence <LOA=2x
and <L'OA=<OKL'+<KL'O=2x. Hence L=L'. K,M,L are collinear
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