<Polygon-2024-271> hint

Let perpendicular feet of C, C', D on line AB are C*. C'*, D*

Since 2C'C'*=CC*+DD* 2[ABC']=[ABC]+[ABD], similarly 2[AFD']=[AFE]+[AED]

Hence sum of areas of given triangles is 3/2 of hexagon ABCDEF

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