Advanced Geometric Problem & Solution (Twice a week update) Now 4641 problems posted.
<Tri-2005-2194>, hint
Triangles DBE and DCF are congruent (DB=DC, <BDE=<CDF, <DBE=<DCF=<DCA=90)
Thus triangle EDF is isosceles and <PDE=<PDF Hence. PE=PF, DPㅗEF
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