<Tri-2025-2204>, hint

By Ceva's BF/FA=BD/DC=AB/AC (c/b)

Let line  BM and line AC  meet at P. Then AC/CP=AF/FB=AC/AB (b/c)

Hence AB=CP.  BF=AB x (c/b+c) DM=CP x( c/(b+c). BF=DM

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