<Qua-2025-775>, hint

Suppose BC=1, BL=t, BK=s,  

triangles BKL and CLM are congruent,  so  CM=t, CL=s, t+s=1( BL+CL=1)

BA/BL=1/t, AD/AK=1/(1-s), Since t+s=1 --->t=1-s. Hence AL and KD are perpendicular

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