Advanced Geometric Problem & Solution (Twice a week update) Now 4733 problems posted.
<Tri-2025-2285>, hint
Since P, A', B,C' are cyclic and <PBC'=<ACB. Let A'C' cuts AC at Q
<C'A'B=<C'PB. Thus triangles PBC' and A'QC are similar <PC'B=<A'QC=90
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