<Tri-2025-2281>, hint

 Since ABDK are cyclic <AKL=<ABD=<B

Since <HAD=90-B=<HLD, H,A,L,D are cyclic, <ALK=<DHH' (AH' is altitude), Thus <ALD=<DHH'=<C, Hence <CAL=<A. A, L, C, D are cyclic  and <CAD=CLD=B-C Thus <ALC=<C+<B-<C=<B

Triangles ACL and ACB are congruent. BC=CL