<Cir-2026-794>, hint

Let<CAD=X, <PQB=Y, <ADB=Z, 

<BCQ=<BCD-<DCQ. Since ADCB are cyclic   and AQPB are cyclic,  PQDC are cyclic

<BCD=180-<BAD=180-(X+Y), <PQB=<PAB, <QPD=<QCD

<BCQ=<BCD-QCD=180-(X+Y)-(90-Z)=180-2(X+Y), <BAD=<DPQ

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