Advanced Geometric Problem & Solution (Twice a week update) Now 4732 problems posted.
<Cir-2026-793 >, hint
Let O be the center of circle , M be the midpoint of PQ.
Since <OMT=90, <ODT=<OBT=90, ODTBM are cyclic. Let <TOD=TOB=X
<TMD=<TOD=<CMP=X ( MC and MD are symmetric wrt MO)
<TMB=<TOB=X. <CMP=<BMT=X. Hence C, M,B are collinear
No comments:
Post a Comment