<Qua-2026-809>, hint

Let <BAM=DAM=X, then <BMA=CNM=X

BF=BA=CD, OM=OC( radius), <OCD=<BCD+<OCB=2X+90-X=90+X

<OMB=<BMN+OMN=180-X+2X-90=90+X

Triangles OBM and ODC are congruent 

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