<Cir-2026-800>, hint

Since CPQ is isosceles PQ ㅗCO (O;enter of circle ABC) Triangles CLA and CNA are congruent (KAxKC=KPxKQ=KLxKN, A,N,C,L are concyclic <CLA=<CNA=90,CL=CN, AC common)

<COB=2<CAB=<LAB hence AL//CO and COㅗPQㅗAL

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