<Tri-2026-2304>, hint
Since PQ//BC, GQ=2/3DC=1/3 BC, GE/EC=1/3, Similarly GF/FB=1/3
Hence EF//BC. Since triangles EGQ and ECB are similar DE cuts GQ at M, midpoint of GQ
GQ=1/6BC GD=1/3AD while BD=1/2BC, triangles DGM and ADBare similar, AB//MD AB//ED
Similarly AC//FD. Finally triangles ABC and DEF are similar.
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