<Tri-2026-2335>, hint


since HPDEF are concyclic

EF/sin EHF=EF/sinA=2PH---<1>, BC/sinA=2R---<2>

<1>/<2>=EF/BC= 2PH/2R. Similarly DE/AB=FD/AC=2PH/2R

Two triangles are similar Hence  ratio of their areas is (2PH/2R) x (2PH/2R)

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