Advanced Geometric Problem & Solution (Twice a week update) Now 4792 problems posted.
<Qua-2026-820>, hint
triangles ABX and YZX are similar, Let Y=t. [ABZY]=1/2+t/2, [XYZ]=2/3
Hence [XAB]/[XYZ]=1^2/t^2=(1/2+t/2+2/3)/(2/3). You get t=2/3
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