KOMATH

Advanced Geometric Problem & Solution (Twice a week update) Now 4603 problems posted.

HOME
PROBLEM
- TRIANGLE
  - EQUILATERAL
    - AREA
    - ANGLE
    - BISECTOR
    - COLLINEARITY
    - CONCURRENCY
    - CENTER
    - CONSTRUCTION
    - CIRCLE
    - DISTANCE
    - LOCUS
    - MEDIANS
    - PERIMETER
    - PERPENDICULAR
    - SIMILAR
    - OTHERS
  - ISOSCELES
    - AREA
    - ANGLE
    - BISECTOR
    - COLLINEARITY
    - CONCURRENCY
    - CENTER
    - CONSTRUCTION
    - CIRCLE
    - DISTANCE
    - LOCUS
    - MEDIANS
    - PERIMETER
    - PERPENDICULAR
    - SIMILAR
    - OTHERS
  - RIGHT
    - AREA
    - ANGLE
    - BISECTOR
    - COLLINEARITY
    - CONCURRENCY
    - CENTER
    - CONSTRUCTION
    - CIRCLE
    - DISTANCE
    - LOCUS
    - MEDIANS
    - PERIMETER
    - PERPENDICULAR
    - SIMILAR
    - OTHERS
  - GENERAL
    - AREA
    - ANGLE
    - BISECTOR
    - COLLINEARITY
    - CONCURRENCY
    - CENTER
    - CONSTRUCTION
    - CIRCLE
    - DISTANCE
    - LOCUS
    - MEDIANS
    - PERIMETER
    - PERPENDICULAR
    - SIMILAR
    - OTHERS
- QUADRILATERALS
  - GENERAL
    - AREA
    - ANGLE
    - BISECTOR
    - CIRCLE
    - CYCLIC
    - COLLINEARITY
    - CONCURRENCY
    - CONSTRUCTION
    - DISTANCE
    - LOCUS
    - SIMILAR
    - OTHERS
  - PARALLELOGRAM
    - AREA
    - ANGLE
    - BISECTOR
    - CIRCLE
    - CYCLIC
    - COLLINEARITY
    - CONCURRENCY
    - CONSTRUCTION
    - DISTANCE
    - LOCUS
    - SIMILAR
    - OTHERS
  - RECTANGLE
    - AREA
    - ANGLE
    - BISECTOR
    - CIRCLE
    - CYCLIC
    - COLLINEARITY
    - CONCURRENCY
    - CONSTRUCTION
    - DISTANCE
    - LOCUS
    - SIMILAR
    - OTHERS
  - SQUARE
    - AREA
    - ANGLE
    - BISECTOR
    - CIRCLE
    - CYCLIC
    - COLLINEARITY
    - CONCURRENCY
    - CONSTRUCTION
    - DISTANCE
    - LOCUS
    - SIMILAR
    - OTHERS
  - TRAPEZOID
    - AREA
    - ANGLE
    - BISECTOR
    - CIRCLE
    - CYCLIC
    - COLLINEARITY
    - CONCURRENCY
    - CONSTRUCTION
    - DISTANCE
    - LOCUS
    - SIMILAR
    - OTHERS
- CIRCLES
  - AREA
  - BISECTOR
  - CHORD
  - CYCLIC
  - COLLINEARITY
  - CONCURRENCY
  - CONSTRUCTION
  - INVERSION
  - LOCUS
  - TANGENT
  - OTHERS
- POLYGON
  - HEXAGON
    - ANGLE
    - AREA
    - CONSTURCTION
    - CIRCLE
    - DISTANCE
    - PERIMETER
    - VECTOR
    - OTHERS
  - PENTAGON
    - ANGLE
    - AREA
    - CONSTURCTION
    - CIRCLE
    - DISTANCE
    - PERIMETER
    - VECTOR
    - OTHERS
  - OTHERS
    - ANGLE
    - AREA
    - CONSTURCTION
    - CIRCLE
    - DISTANCE
    - PERIMETER
    - VECTOR
    - OTHERS
- SOLID
  - BOX
    - AREA
    - VOLUME
    - OTHERS
    - LOCUS
    - DISTANCE
  - TETRAHEDRON
    - AREA
    - VOLUME
    - OTHERS
    - LOCUS
    - DISTANCE
  - GENERAL
    - AREA
    - VOLUME
    - OTHERS
    - LOCUS
    - DISTANCE
- CONSTRUCTIONS
  - CIRCLE
    - BISECT
    - PARALLEL
    - PERPENDICULAR
    - OTHERS
  - LINE
    - BISECT
    - PARALLEL
    - PERPENDICULAR
    - OTHERS
  - QUADRILATERAL
    - BISECT
    - PARALLEL
    - PERPENDICULAR
    - OTHERS
  - TRIANGLE
    - BISECT
    - PARALLEL
    - PERPENDICULAR
    - OTHERS
  - OTHERS
    - BISECT
    - PARALLEL
    - PERPENDICULAR
    - OTHERS
- TRIGONOMETRY
  - CIRCLE
    - EVALUATION
    - INEQUALITY
    - RELATION
    - OTHERS
  - QUADRILATERAL
    - EVALUATION
    - INEQUALITY
    - RELATION
    - OTHERS
  - TRIANGLE
    - EVALUATION
    - INEQUALITY
    - RELATION
    - OTHERS
  - GENERAL
    - EVALUATION
    - INEQUALITY
    - RELATION
    - OTHERS
SOLUTION
SOURCE
LINK
COPYRIGHT

<Tri-2025-2218>, general, orthocenter

작성자: komath

라벨: center, general, problem, triangle

No comments:

Total Pageviews

Ads

Weekly

(no title)

<Solid-2024-248>, hint Suppose TB=TC, isosceles, and <CTD=90, CTD is right triangle and TT' is height of TABCD, O is center of...
(no title)

<Cir-2023-754>, hint B,M,X,C are concyclic <MBC=<XMC=<DAC Similarly <XDC=<XNC=<BEC Hence triangles XMN and YAE are...
(no title)

<Tri-2025-2183>, hint Suppose AM cuts the circumcircle of ABC at O and I is incenter of ABC. Since <OBI=<OIB=<OCI, O is the c...
(no title)

<Tri-2025-2183>, isosceles, angle <Romania TST 2021>
(no title)

<Solid-2025-257>, hint Let O be the center of circumscribed sphere of ABCD, and let vectors OA=a, OB=b, OC=c, OD=d. P=t(a+c)/2+(1-t)(b...
(no title)

<Tri-2023-2062>, hint
(no title)

<Tri-2023-2079>, hint Radical axis theorem
(no title)

<Tri-2024-2151>, hint Since DE is bisector of <BEC BE/EC=BD/DC and BF=BE AF=CE. BF/FA=BD/DC ---> FD//AC ---> <FDE=<C...
(no title)

<Tri-2025-2185>, hint Suppose incircle of ABC touches BC, CA, AB at D,E,F respectively Consider trianges IDP, IEN, IFM which are cong...
Tri-2017-1327, hint

.

Powered by Blogger.

No comments:

Post a Comment